Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M. If the block rises to a height h, the initial velocity of the block will be
Text Solution
Verified by ExpertsThe correct answer is:
A
Initial K.E. of block when bullet strikes to it
$= \frac{1}{2} (m + M) V^{2}$
Due to this K.E. block will rise to a height h.
Its potential energy = $(m + M)gh.$
By the law of conservation of energy
$\frac{1}{2}(m+M)V^{2} = (m+M)gh$ ∴ ∴ $v = \sqrt{2gh}$
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