A

Step 1: Understand that 'g' is the acceleration due to gravity.
Step 2: The value of 'g' at the equator is currently affected by two main factors: the gravitational pull of the Earth and the centrifugal force due to its rotation.
Step 3: The centrifugal force acts outward and reduces the effective value of 'g' at the equator.
Step 4: The formula for effective gravity at the equator is:
$$ g' = g - R \omega^2 $$
where \( g' \) is the effective gravity, \( g \) is the true gravitational acceleration, \( R \) is the radius of the Earth, and \( \omega \) is the angular velocity of the Earth.
Step 5: If the Earth stops rotating, then \( \omega \) becomes 0, and the centrifugal force disappears. Therefore, we have:
$$ g' = g - 0 $$
Thus, \( g' = g \) which means the effective value of 'g' will increase as the centrifugal force is no longer present to counteract the force of gravity.
Therefore, the value of 'g' at the equator will increase.