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CGP EDU Academic Team
Published on: September 11, 2026
A body of mass m rises to height h = R/5 from the earth's surface, where R is earth's radius. If g is acceleration due to gravity at earth's surface, the increase in potential energy is
$(a) mgh \quad (b) \frac{4}{5} mgh \quad (c) \frac{5}{6} mgh \quad (d) \frac{6}{7} mgh$
Text Solution
Verified by ExpertsThe correct answer is:
C
$\Delta U = \frac{mgh}{1 + h/R}$
Substituting R = 5 h we get $\Delta U = \frac{mgh}{1+1/5} = \frac{5}{6} mgh$
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