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CGP EDU Academic Team
Published on: September 12, 2026
In CGS system, the Young's modulus of a steel wire is $2 \times 10^{12}$ . To double the length of a wire of unit cross-section area, the force required is
Text Solution
Verified by ExpertsThe correct answer is:
B
To double the length of wire, Stress = Young's modulus
$\therefore \frac{F}{A} = 2 \times 10^{12} \frac{\text{dyne}}{\text{cm}^2} .$
If A = 1 then F = 2 × 10 12 dyne
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