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CGP EDU Academic Team
Published on: September 12, 2026
A rubber pipe of density $1.5 \times 10^{3} \mathrm{N}/\mathrm{m}^{2}$ and Young's modulus $5 \times 10^{6} \mathrm{N} / \mathrm{m}^{2}$ is suspended from the roof. The length of the pipe is 8 m. What will be the change in length due to its own weight
Text Solution
Verified by ExpertsThe correct answer is:
D
$l = \frac{L^2 \mathrm{dg}}{2Y} = \frac{(8)^2 \times 1.5 \times 10^3 \times 10}{2 \times 5 \times 10^6} = 9.6 \times 10^{-2} \mathrm{m}$
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