The length of an elastic string is a meter when the longitudinal tension is 4 N and b meter when the longitudinal tension is 5 N. The length of the string in meter when the longitudinal tension is 9 N is
Text Solution
Verified by ExpertsB
Let L is the original length of the wire and K is force constant of wire.
Final length = initial length + elongation
$L' = L + \frac{F}{K}$
For first condition $a = L + \frac{4}{k}$ …(i)
For second condition $b = L + \frac{5}{k}$ …(ii)
By solving (i) and (ii) equation we get
L = 5a - 4b and $K = \frac{1}{b - a}$
Now when the longitudinal tension is 9N, length of the string = $L + \frac{g}{k}$ = $5a - 4b + 9(b - a)$ = 5b = 4a .
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems