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CGP EDU Academic Team
Published on: September 12, 2026
The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted through an angle of 30°. Then angle of shear is
Text Solution
Verified by ExpertsThe correct answer is:
B
Angle of shear $\varphi = \frac{r \theta}{L} = \frac{4 \times 10^{-1}}{100} \times 30^{\circ} = 0.12^{\circ}$
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