If one end of a wire is fixed with a rigid support and the other end is stretched by a force of 10 N, then the increase in length is 0.5 mm. The ratio of the energy of the wire and the work done in displacing it through 1.5 mm by the weight is
Text Solution
Verified by ExpertsThe correct answer is:
C
Work done in stretching a wire
= 
Work done to displace it through 1.5 mm

The ratio of above two work = 1 : 2
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If the potential energy of a spring is V on stretching it by 2 cm, then its potential energy when i…
The work done in stretching an elastic wire per unit volume is or strain energy in a stretched stri…
Calculate the work done, if a wire is loaded by 'Mg' weight and the increase in length is 'l'
Two wires of same diameter of the same material having the length l and 2l. If the force F is appli…
A 5-meter-long wire is fixed to the ceiling. A weight of 10 kg is hung at the lower end and is 1 me…
If the force constant of a wire is K, the work done in increasing the length of the wire by l is