Wires A and B are made from the same material. A has twice the diameter and three times the length of B. If the elastic limits are not reached, when each is stretched by the same tension, the ratio of energy stored in A to that in B is
Text Solution
Verified by ExpertsB
$\mathrm{U} = \frac{1}{2} \mathrm{Fl} = \frac{\mathrm{F}^2 \mathrm{L}}{2 \mathrm{AY}}; \quad \mathrm{U} \propto \frac{\mathrm{L}}{r^2} \text{ (F and Y are constant)}$ $\therefore \frac{\mathrm{U}_A}{\mathrm{U}_B} = \left(\frac{\mathrm{L}_A}{\mathrm{L}_B}\right) \times \left(\frac{r_A}{r_B}\right)^2 = (3) \times \left(\frac{1}{2}\right)^2 = \frac{3}{4}$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems