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CGP EDU Academic Team
Published on: September 12, 2026
There are two wires of same material and same length while the diameter of second wire is 2 times the diameter of first wire, then ratio of extension produced in the wires by applying same load will be
Text Solution
Verified by ExpertsThe correct answer is:
D
$l = \frac{\mathrm{FL}}{\mathrm{AY}} \therefore l \propto \frac{1}{r^2} \text{ (F, L and Y are constant)}$ $\frac{l_1}{l_2} = \left(\frac{r_2}{r_1}\right)^2 = (2)^2 = 4$
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