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CGP EDU Academic Team
Published on: September 12, 2026
8000 identical water drops are combined to form a big drop. Then the ratio of the final surface energy to the initial surface energy of all the drops together is
Text Solution
Verified by ExpertsThe correct answer is:
C
As volume remains constant $R^{3} = 8000r^{3} \therefore R = 20r$
$\frac{\text{Surface energy of one big drop}}{\text{Surface energy of 8000 small drop}} = \frac{4 \pi R^{2} T}{8000 \, 4 \pi r^{2} T} = \frac{R^{2}}{8000 r^{2}} = \frac{(20 r)^{2}}{8000 r^{2}} = \frac{1}{20}$
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