Two parallel glass plates are dipped partly in the liquid of density 'd' keeping them vertical. If the distance between the plates is 'x', surface tension for liquids is T and angle of contact is $\theta$ , then rise of liquid between the plates due to capillary will be
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Let the width of each plate is b and due to surface tension liquid will rise upto height h then upward force due to surface tension
= $2TpB \cos \theta$ …(i)
Weight of the liquid rises in between the plates
= $\nabla dg = (b \times n) dg$ …(ii)
Equating (i) and (ii) we get, $2T \cos \theta = b x h d g$
$\therefore h = \frac{2T \cos \theta}{x d g}$
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