A soap bubble of radius R is blown. After heating the solution a second bubble of radius 2 R is blown. The work required to blow the second bubble in comparison to that required for the first bubble is
Text Solution
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Work done to form a bubble of radius R
$W_1 = 8 \pi R^2 T_1$
Work done to form a bubble of radius 2R
$W_2 = 8 \pi (2R)^2 T_2$ $= 32 \pi R^{2} T_{2}$ ∴ ∴ $\frac{W_1}{W_2} = \frac{T_1}{2T_2}$
If surface tension of soap solution is same then
$W_2 = 4 W_1$
But in the problem temperature of solution is increased so its surface tension decreases.
∴ ∴ $W_2 < 4W_1$
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