Let the total volume of ice-berg is V and its density is ρ ρ . If this ice-berg floats in water with

volume V in inside it then $V_{in} \sigma g = V \rho g$ ⇒ ⇒ $\mathbf{V}_{in} = \left(\frac{\rho}{\sigma}\right) \mathbf{V}$ [ $\overline{\sigma} =$ density of water]

or $\mathbf{V}_{out} = \mathbf{V} - \mathbf{V}_{in} = \left(\frac{\sigma - \rho}{\sigma}\right) \mathbf{V}$

⇒ ⇒ $\frac{V_{out}}{V} = \left(\frac{\sigma - \rho}{\sigma}\right) = \frac{1000 - 900}{1000} = \frac{1}{10}$

∴ ∴ $V_{\text{out}} = 10\%$ of V