A manometer connected to a closed tap reads 3.5 × 10 5 N/m 2 . When the valve is opened, the reading of manometer falls to 3.0 × 10 5 N/m 2 , then velocity of flow of water is
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Bernoulli's theorem for unit mass of liquid
$\frac{P}{\rho} + \frac{1}{2} v^{2} =$ constant
As the liquid starts flowing, it pressure energy decreases $\frac{1}{2} v^{2} = \frac{P_{1} - P_{2}}{\rho}$ $\Rightarrow \frac{1}{2} v^{2} = \frac{3.5 \times 10^{5} - 3 \times 10^{5}}{10^{3}} \Rightarrow v^{2}$
$\frac{2 \times 0.5 \times 10^{5}}{10^{3}} \Rightarrow v^{2} = 100 \Rightarrow v = 10 \, m/s$
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