A square plate of 0.1 m side moves parallel to a second plate with a velocity of 0.1 m/s, both plates being immersed in water. If the viscous force is 0.002 N and the coefficient of viscosity is 0.01 poise, distance between the plates in m is
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$A = (0.1)^2 = 0.01 m^2$ , $\eta = 0.01 \text{ Poise} = 0.001 \text{ Decapoise}$ (M.K.S. unit),
dv = 0.1 m/s and F = 0.002 N
$\mathrm{F} = \eta A \frac{\mathrm{dv}}{\mathrm{dx}} \quad \therefore \quad \mathrm{dx} = \frac{\eta A \mathrm{dv}}{\mathrm{F}} = \frac{0.001 \times 0.01 \times 0.1}{0.002} = 0.0005 \mathrm{m}.$
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