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CGP EDU Academic Team
Published on: September 12, 2026
A manometer connected to a closed tap reads $4.5 \times 10^{5}$ pascal. When the tap is opened the reading of the manometer falls to $4 \times 10^{5}$ pascal. Then the velocity of flow of water is
Text Solution
Verified by ExpertsThe correct answer is:
D
$\frac{P_1 - P_2}{\rho g} = \frac{v^2}{2g} \Rightarrow \frac{4.5 \times 10^5 - 4 \times 10^5}{10^3 \times g} = \frac{v^2}{2g} : \therefore v = 10 \mathrm{m/s}$
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