A vessel contains 110 g of water. The heat capacity of the vessel is equal to 10 g of water. The initial temperature of water in vessel is 10°C. If 220 g of hot water at 70°C is poured in the vessel, the final temperature neglecting radiation loss, will be
Text Solution
Verified by ExpertsThe correct answer is:
D
Let final temperature of water be θ θ
Heat taken = Heat given
110 × × 1 ( θ θ – 10) + 10 ( θ θ – 10) = 220 × × 1 (70 – θ θ )
⇒ ⇒ θ θ = 48.8°C ≈ ≈ 50°C.
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