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CGP EDU Academic Team
Published on: September 12, 2026
A diatomic gas initially at 18°C is compressed adiabatically to one-eighth of its original volume. The temperature after compression will be
Text Solution
Verified by ExpertsThe correct answer is:
C
$\mathrm{TV}^{\gamma-1}=$ constant
$\Rightarrow T_2 = T_1 \left(\frac{V_1}{V_2}\right)^{\gamma - 1} = (273 + 18) \left(\frac{V}{V/8}\right)^{0.4} = 668 \mathrm{K}$
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