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CGP EDU Academic Team
Published on: September 12, 2026
At $27^\circ C$ a gas is suddenly compressed such that its pressure becomes $\frac{1}{8} \mathrm{th}$ of original pressure. Temperature of the gas will be $(\gamma = 5/3)$
Text Solution
Verified by ExpertsThe correct answer is:
D
$\mathrm{TYP^{1-\gamma} = constant \Rightarrow T \propto P^{\frac{\gamma-1}{\gamma}}}$ $\Rightarrow \frac{T_2}{T_1} = \left(\frac{P_2}{P_1}\right)^{\frac{\gamma-1}{\gamma}} = \left(\frac{1}{8}\right)^{\frac{5/3-1}{5/3}}$ $\mathrm{T_2 = 300 \times \left(\frac{1}{8}\right)^{0.4} = 131K = -142^\circ C}$
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