One mole of an ideal gas at an initial temperature of T K d…

Physics Thermodynamics Adiabatic Process Single Correct MCQ

Published on: September 13, 2026

One mole of an ideal gas at an initial temperature of T K does 6 R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of gas will be

$(T + 2.4)K$

(T - 2.4)K

$(T + 4)K$

$(T - 4) K$

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The correct answer is:

$W = \frac{R(T_i - T_f)}{\gamma - 1} \Rightarrow 6R = \frac{R(T - T_f)}{\left(\frac{5}{3} - 1\right)} \Rightarrow T_f = (T - 4)K.$

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