Published by:
CGP EDU Academic Team
Published on: September 12, 2026
If the radius and length of a copper rod are both doubled, the rate of flow of heat along the rod increases
Text Solution
Verified by ExpertsThe correct answer is:
B
$Q \propto \frac{A}{l} \propto \frac{r^2}{l} \Rightarrow \frac{Q_2}{Q_1} = \frac{r_2^2}{r_1^2} \times \frac{l_1}{l_2} \Rightarrow \frac{Q_2}{Q_1} = \frac{4}{1} \times \frac{1}{2} \Rightarrow Q_2 = 2Q_1$
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