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CGP EDU Academic Team
Published on: September 12, 2026
A metal ball of surface area $200 \text{ cm}^2$ and temperature 527^\circ C is surrounded by a vessel at $27^\circ C$ . If the emissivity of the metal is 0.4, then the rate of loss of heat from the ball is $(\sigma = 5.67 \times 10^{-8} \mathrm{J/m^2 \cdot s \cdot K^4})$
Text Solution
Verified by ExpertsThe correct answer is:
C
Rate of heat loss $E = \sigma e A (T^4 - T_0^4)$
$= 5.67 \times 10^{-8} \times 0.4 \times 200 \times 10^{-4}$ × × $[(273 + 527)^4 - (273 + 27)^4]$
$= 5.67 \times 10^{-8} \times 0.4 \times 200 \times 10^{-4}$ × × $(800)^{4} - (300)^{4}$ =182J/sec
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