The two opposite faces of a cubical piece of iron (thermal conductivity = 0.2 CGS units) are at $100^\circ \mathrm{C}$ and $0^\circ C$ in ice. If the area of a surface is $4 \mathrm{cm}^2$ , then the mass of ice melted in 10 minutes will be
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$Q = mL = KA \frac{(\theta_1 - \theta_2)}{l} t \Rightarrow m = \frac{1}{L} \times KA \frac{(\theta_1 - \theta_2)}{l} \times t = \frac{1}{80} \times 0.2 \times 4 \times \frac{(100 - 0)}{\sqrt{4}} \times 10 \times 60 \; (\because l^2 = 4 \Rightarrow l = \sqrt{4}) = \frac{0.2 \times 4 \times 100 \times 600}{80 \times 2} = 300 \text{ gm}$
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