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CGP EDU Academic Team
Published on: September 12, 2026
Two equations of two S.H.M. are $y = a \sin(\omega t - \alpha)$ and $y = b \cos(\omega t - \alpha)$ . The phase difference between the two is
Text Solution
Verified by ExpertsThe correct answer is:
C
$y = a \sin(\omega t - \alpha) = a \cos\left(\omega t - \alpha - \frac{\pi}{2}\right)$
Another equation is given $y = \cos(\omega t - \alpha)$
So, there exists a phase difference of $\frac{\pi}{2} = 90^\circ$
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