Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A particle of mass 10 grams is executing simple harmonic motion with an amplitude of 0.5 m and periodic time of (π/5) seconds. The maximum value of the force acting on the particle is
Text Solution
Verified by ExpertsThe correct answer is:
D
Maximum force $= m(a\omega^{2}) = ma\left(\frac{4\pi^{2}}{T^{2}}\right)$
$= 0.5 \left(\frac{4 \pi^{2}}{\pi^{2} / 25}\right) \times 0.01 = 0.5 \mathrm{N}$
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