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CGP EDU Academic Team
Published on: September 12, 2026
A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. If the lift accelerates upwards with an acceleration $g/4$ , then the period of the pendulum will be
Text Solution
Verified by ExpertsThe correct answer is:
C
In stationary lift $T = 2 \pi \sqrt{\frac{l}{g}}$
In upward moving lift $T' = 2\pi \sqrt{\frac{1}{(g + a)}}$
( a Acceleration of lift)
$\Rightarrow$ $\frac{T'}{T} = \sqrt{\frac{g}{g+a}} = \sqrt{\frac{g}{\left(g+\frac{bg}{4}\right)}} = \sqrt{\frac{4}{5}}$ $\Rightarrow \mathrm{T}' = \frac{2 \mathrm{T}}{\sqrt{5}}$
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