C

Step 1: Understand that the wavelength of light ($\lambda_v$) is typically shorter than that of sound ($\lambda_s$).
Step 2: In a general comparison, visible light has wavelengths ranging from approximately 400 nm to 700 nm, while the wavelengths of sound can be much longer, typically in meters, depending on frequency.
Step 3: This implies that $\lambda_v < \lambda_s$.
Step 4: Therefore, the correct relation is $\lambda_s > \lambda_v$.
Conclusively, the correct answer is Option C: $\lambda_s > \lambda_v$.