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CGP EDU Academic Team
Published on: September 12, 2026
The equation of a transverse wave travelling on a rope is given by $y = 10 \sin \pi (0.01x - 2.00t)$ where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about
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A
The given equation is $y = 10 \sin(0.01 \pi x - 2 \pi t)$
Hence $\omega$ coefficient of t = 2 π π
⇒ ⇒ Maximum speed of the particle $\mathbf{v_{max}} = a \omega = 10 \times 2 \pi$
= 10 × × 2 × × 3.14 = 62.8 ≈ ≈ 63 cm/s
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