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CGP EDU Academic Team
Published on: September 12, 2026
Equation of motion in the same direction are given by
$y_1 = 2a \sin(\omega t - kx)$ and $y_{2} = 2a \sin(\omega t - kx - \theta)$
The amplitude of the medium particle will be
Text Solution
Verified by ExpertsThe correct answer is:
C
Resultant amplitude
$A_{R} = 2A \cos \left(\frac{\theta}{2}\right) = 2 \times (2a) \cos \left(\frac{\theta}{2}\right) = 4a \cos \left(\frac{\theta}{2}\right)$
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