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CGP EDU Academic Team
Published on: September 11, 2026
A 1 cm long string vibrates with fundamental frequency of 256 Hz. If the length is reduced to $\frac{1}{4} \text{ cm}$ keeping the tension unaltered, the new fundamental frequency will be
Text Solution
Verified by ExpertsThe correct answer is:
D
$n \propto \frac{1}{l} \Rightarrow \frac{n_2}{n_1} = \frac{l_1}{l_2}$
⇒ ⇒ $n_{2} = \frac{l_{1}}{l_{2}} n_{1}$
$= \frac{1 \times 256}{1/4} = 1024 \mathrm{Hz}$
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