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CGP EDU Academic Team
Published on: September 12, 2026
Two closed organ pipes, when sounded simultaneously gave 4 beats per sec. If longer pipe has a length of 1m. Then length of shorter pipe will be, (v = 300 m/s)
Text Solution
Verified by ExpertsThe correct answer is:
B
For first pipe $n_1 = \frac{v}{4l_1}$ and for second pipe $n_2 = \frac{v}{4l_2}$ So, number of beats $= n_2 - n_1 = 4$ $\Rightarrow 4 = \frac{v}{4} \left(\frac{1}{l_2} - \frac{1}{l_1}\right) \Rightarrow 16 = 300 \left(\frac{1}{l_2} - \frac{1}{l_1}\right)$ $\Rightarrow l_2 = 94.9 \text{cm}$
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