The ends of a stretched wire of length L are fixed at 
and 
In one experiment, the displacement of the wire is 
and energy is 
, and in another experiment its displacement is 
and energy is 
. Then
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
Energy (E) ∝ ∝ (Amplitude) 2 (Frequency) 2
Amplitude is same in both the cases, but frequency 2 
in the second case is two times the frequency 
in
the first case. Hence 
.
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