Published by:
CGP EDU Academic Team
Published on: September 11, 2026
The ratio of the forces between two small spheres with constant charge (a) in air $(b)$ in a medium of dielectric constant K is
Text Solution
Verified by ExpertsThe correct answer is:
B
$F_a = \frac{q_1 q_2}{4 \pi \varepsilon_0 r^2}, \quad F_b = \frac{q_1 q_2}{K 4 \pi \varepsilon_0 r^2}$ ⇒ ⇒ $F_a : F_b = K : 1$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The law, governing the force between electric charges is known as
When the distance between the charged particles is halved, the force between them becomes
There are two charges +1 microcoulombs and +5 microcoulombs. The ratio of the forces acting on them…
A charge q 1 exerts some force on a second charge q 2 . If third charge q 3 is brought near, the fo…
$F_g$ and $F_e$ represents gravitational and electrostatic force respectively between electrons sit…
A soap bubble is given a negative charge, then its radius