Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The distance between the two charges $25 \mu C$ and $36 \mu C$ is $11\,\mathrm{cm}$ At what point on the line joining the two, the intensity will be zero
Text Solution
Verified by ExpertsThe correct answer is:
A
Suppose electric field is zero at point N in the figure then
At N |E 1 | = |E 2 |
which gives $x_1 = \frac{x}{\sqrt{\frac{Q_2}{Q_1} + 1}} = \frac{11}{\sqrt{\frac{36}{25} + 1}} = 5cm$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A charge q is placed at the center of the line joining two equal charges Q. The system of the three…
Inside a hollow charged spherical conductor, the potential
Two small spheres each carrying a charge q are placed r meter apart. If one of the spheres is taken…
The electric charge in uniform motion produces
Two charged spheres of radii 10 cm and 15 cm are connected by a thin wire. No current will flow, if…
The electric field inside a spherical shell of uniform surface charge density is