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CGP EDU Academic Team
Published on: September 12, 2026
The distance between a proton and electron both having a charge $1.6 \times 10^{-19} \text{ coulomb}$ , of a hydrogen atom is $10^{-10}$ metre . The value of intensity of electric field produced on electron due to proton will be
Text Solution
Verified by ExpertsThe correct answer is:
D
$E = \frac{q}{4 \pi \epsilon_0 r^2}$
$=9 \times 10^{9} \times \frac{1.6 \times 10^{-19}}{(10^{-10})^{2}} = 1.44 \times 10^{11} \mathrm{N/C}$
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