Four identical charges $+ 50 \mu C$ each are placed, one at each corner of a square of side $2\,\mathrm{m}$ . How much external energy is required to bring another charge of $+ 50 \mu C$ from infinity to the center of the square
$\left(\text{Given } \frac{1}{4 \pi \varepsilon_0} = 9 \times 10^9 \frac{\mathrm{Nm}^2}{\mathrm{C}^2} \right)$
Text Solution
Verified by ExpertsA
Potential at the center of square
$V = 4 \times \left(\frac{9 \times 10^{9} \times 50 \times 10^{-6}}{2 / \sqrt{2}}\right) = 90 \sqrt{2} \times 10^{4} V$
Work done in bringing a charge (q = 50 μ μ C) from ∞ ∞ to centre (O) of the square is $W = q(V_0 - V_\infty) = qV_0$
⇒ ⇒ $W = 50 \times 10^{-6} \times 90 \sqrt{2} \times 10^{4} = 64J$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems