Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A body executing simple harmonic motion has a maximum acceleration equal to $24 meters/sec^{2}$ and maximum velocity equal to 16 meters/sec . The amplitude of the simple harmonic motion is
(a) $\frac{32}{3}$ metres (b) $\frac{3}{32}$ metres (c) $\frac{1024}{9}$ metres (d) $\frac{64}{9}$ metres
Text Solution
Verified by ExpertsThe correct answer is:
A
Maximum velocity $= a \omega$ = 16
Maximum acceleration $= \omega^{2} a = 24$
$\Rightarrow a = \frac{(a \omega)^2}{\omega^2 a} = \frac{16 \times 16}{24} = \frac{32}{3} \mathrm{m}$
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