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CGP EDU Academic Team
Published on: September 12, 2026
The relation between time and displacement for two particles is given by
$y_{1} = 0.06 \sin 2 \pi (0.04 t + \phi_{1})$ , $y_{2} = 0.03 \sin 2 \pi (1.04 t + \phi_{2})$
The ratio of the intensity of the waves produced by the vibrations of the two particles will be
Text Solution
Verified by ExpertsThe correct answer is:
C
$\frac{I_1}{I_2} = \frac{a_1^2}{a_2^2} = \left(\frac{0.06}{0.03}\right)^2 = \frac{4}{1}$
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