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CGP EDU Academic Team
Published on: September 12, 2026
A transverse progressive wave on a stretched string has a velocity of $10\,\mathrm{ms}^{-1}$ and a frequency of 100 Hz. The phase difference between two particles of the string which are 2.5 cm apart will be
$(a) \frac{\pi}{8} \quad (b) \frac{\pi}{4} \quad (c) \frac{3\pi}{8} \quad (d) \frac{\pi}{2}$
Text Solution
Verified by ExpertsThe correct answer is:
D
$v = n\lambda \Rightarrow \lambda = 10cm$
Phase difference $\frac{2\pi}{\lambda} \times \text{Path difference} \frac{2\pi}{10} \times 2.5 = \frac{\pi}{2}$
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