A

To relate the wavelengths of light (\(\lambda_V\)) and sound (\(\lambda_S\)), we consider the speed of each wave. The speed of light in a vacuum is approximately \(c \approx 3 \times 10^8\) m/s, while the speed of sound in air at room temperature is approximately \(v \approx 343\) m/s.
The general wave equation relates the speed (v), frequency (f), and wavelength (\(\lambda\)) as follows:
\(v = f \cdot \lambda\)
For light, \(c = f_V \cdot \lambda_V\)
For sound, \(v = f_S \cdot \lambda_S\)
Since the frequency of light is much higher than that of sound, their wavelengths will also be in a similar ratio. Given that electromagnetic waves (light) have much shorter wavelengths compared to sound waves, we conclude that \(\lambda_V > \lambda_S\). Thus, the correct relation is \(\lambda_V > \lambda_S\).
Therefore, the answer is A.