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CGP EDU Academic Team
Published on: September 12, 2026
If the equation of transverse wave is $y = 5 \sin 2 \pi \left[\frac{t}{0.04} - \frac{x}{40}\right]$ , where distance is in cm and time in second, then the wavelength of the wave is
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B
Comparing with $y = a \sin 2 \pi \left[\frac{t}{T} - \frac{x}{\lambda}\right]$ ⇒ ⇒ $\lambda = 40 \text{ cm}$
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