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CGP EDU Academic Team
Published on: September 12, 2026
Two spheres $\Delta_A$ and $B$ of radius 4 cm and $6 \mathrm{cm}$ are given charges of $80 \mu C$ and $40 \mu c$ respectively. If they are connected by a fine wire, the amount of charge flowing from one to the other is
Text Solution
Verified by ExpertsThe correct answer is:
D
Total charge $Q = 80 + 40 = 120 \, \mu C$ .
By using the formula $Q_1' = Q \left[\frac{r_1}{r_1 + r_2}\right]$ .
New charge on sphere A is $Q_A' = Q \left[\frac{r_A}{r_A + r_B}\right]$
$= 120 \left[\frac{4}{4+6}\right] = 48 \mu C$ .
Initially it was $80 \mu C$ i.e., $32 \mu C$ charge flows from A to B.
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