Two spheres of radius a and b respectively are charged and …

Physics Electrostatics Potential & Capacitance Electric Field and Potential,Defference,Energy and Dipole Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: September 12, 2026

Two spheres of radius a and b respectively are charged and joined by a wire. The ratio of electric field of the spheres is

a / b

$\frac{b}{a}$

$a^{2} / b^{2}$

$b^{2} \,/\, a^{2}$

Text Solution

Verified by Experts

The correct answer is:

Joined by a wire means they are at the same potential. For same potential $\frac{kQ_1}{a_1} = \frac{kQ_2}{a_2}$ ⇒ ⇒ $\frac{Q_1}{Q_2} = \frac{a}{b}$

Further, the electric field at the surface of the sphere having radius R and charge Q is $\frac{kQ}{R^2} \cdot$

∴ ∴ $\frac{E_1}{E_2} = \frac{kQ_1 / a^2}{kQ_2 / b^2} = \frac{Q_1}{Q_2} \times \frac{b^2}{a^2} = \frac{b}{a}$

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