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CGP EDU Academic Team
Published on: September 12, 2026
A charged particle of mass 0.003 gm is held stationary in space by placing it in a downward direction of electric field of $6 \times 10^{4} \, \mathrm{N/C}$ . Then the magnitude of the charge is
Text Solution
Verified by ExpertsThe correct answer is:
B
By using $QE = mg$
⇒ ⇒ $Q = \frac{mg}{E} = \frac{0.003 \times 10^{-3} \times 10}{6 \times 10^{4}}$ = 5 × × 10 –10 C
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