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CGP EDU Academic Team
Published on: September 12, 2026
A thin spherical conducting shell of radius R has a charge q. Another charge Q is placed at the center of the shell. The electrostatic potential at a point p a distance $\frac{R}{2}$ from the center of the shell is
Text Solution
Verified by ExpertsThe correct answer is:
D
Electric potential at P
$V = \frac{k.Q}{R/2} + \frac{k.q}{R}$
$= \frac{2Q}{4 \pi \epsilon_0 R} + \frac{q}{4 \pi \epsilon_0 R}$
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