A cylinder of radius R and length L is placed in a uniform …

Physics Electrostatics Potential & Capacitance Electric Flux and Gauss's Law Single Correct MCQ

Published on: September 11, 2026

A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux for the surface of the cylinder is given by

$2 \pi R^{2} E$

$\pi R^{2} / E$

$\left(\pi R^{2} - \pi R\right) / E$

Zero

Text Solution

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The correct answer is:

Flux through surface A $\phi_A = E \times \pi R^2$ and $\phi_{B} = - E \times \pi R^{2}$

Flux through curved surface C $= \oint \vec{E} \cdot d\vec{s} = \oint E \, ds \cos 90^\circ$ = 0

∴ ∴ Total flux through cylinder $= \phi_{A} + \phi_{B} + \phi_{C}$ = 0

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