Home Physics Electrostatics Potential & Capacitance Capacitance In a parallel plate condenser, the radius of…
Physics Electrostatics Potential & Capacitance Capacitance Single Correct MCQ
Published on: September 12, 2026

In a parallel plate condenser, the radius of each circular plate is $12cm$ and the distance between the plates is $5\,m\,m$ . There is a glass slab of 3 m m thick and of radius 12cm with dielectric constant 6 between its plates. The capacity of the condenser will be

A
$144 \times 10^{-9} F$
B
$40pF$
C
$160pF$
D
$1.44 \mu F$

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Text Solution

Verified by Experts
The correct answer is:
C

$C = \frac{\varepsilon_0 A}{d - t + \frac{t}{K}} = \frac{1}{4 \pi \times 9 \times 10^9} \cdot \frac{\pi (0.12)^2}{\left(2 + \frac{1}{2}\right) 10^{-3}}$

$= \frac{2 \times 144 \times 10^{-10}}{36 \times 5} = 160 pF$

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