A parallel plate capacitor is charged and the charging battery is then disconnected. If the plates of the capacitor are moved further apart by means of insulating handles, then
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When the battery is disconnected, the charge will remain same in any case.
Capacitance of a parallel plate capacitor is given by $C = \frac{\varepsilon_0 A}{d}$
When d is increased, capacitance will decreases and because the charge remains the same, so according to $q = CV,$ the voltage will increase, Hence the electrostatics energy stored in the capacitor will increase.
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