Capacitance of a parallel plate capacitor becomes 4/3 times its original value if a dielectric slab of thickness t = d/2 is inserted between the plates (d is the separation between the plates). The dielectric constant of the slab is
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$C_{air} = \frac{\varepsilon_0 A}{d}$ , with dielectric slab C ′ ′ = $\frac{\varepsilon_0 A}{\left(d - t + \frac{t}{k}\right)}$
Given $c' = \frac{4}{3} c \Rightarrow$ $\frac{\varepsilon_0 A}{\left(d - t + \frac{t}{k}\right)} = \frac{4}{3} \times \frac{\varepsilon_0 A}{d}$
$\Rightarrow K = \frac{4t}{4t - d} = \frac{4(d/2)}{4[(d/2) - d]} = 2$
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